I am sharing some data using whatsapp, and I want to open a specific activity in my app when user press deep link from whatsapp
I have the following schema
myapp://openapp?type=banner&id=10
whatsapp share the link as a normal text not as url and also I can't open my app when user press it
can anyone help please ?
EDIT
this is my sharing method
public static void openWhatsApp(Context mContext) {
PackageManager pm = mContext.getPackageManager();
try {
Intent whatsAppIntent = new Intent(Intent.ACTION_SEND);
whatsAppIntent.setType("text/plain");
String text = "myapp://openapp?type=banner&id=10";
PackageInfo info=pm.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
whatsAppIntent.setPackage("com.whatsapp");
whatsAppIntent.putExtra(Intent.EXTRA_TEXT, text);
mContext.startActivity(Intent.createChooser(whatsAppIntent, mContext.getString(R.string.share_with)));
} catch (NameNotFoundException e) {
Toast.makeText(mContext, "WhatsApp not Installed", Toast.LENGTH_SHORT).show();
}
}
I don't know if it's possible. It may be that WhatsApp only highlights links with certain protocols (i.e. http, https). In this case, you could go for a work-around if you are depending on this feature:
Let the user share a link to http://your-server.com/forward?type=banner&id=10
On your-server.com
, you re-direct the user within the forward
file (or via server configuration) to myapp://openapp?type=banner&id=10
.
Of course this is not pretty, but browsers can handle these app-links. This will not be pretty, since the user will at first open a browser to process your http link, from which the user will be redirected.
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