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Android: How to programmatically access the device serial number shown in the AVD manager (API Version 8)

How do I programmatically access the value shown in the image below ?

enter image description here

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Heshan Perera Avatar asked Jun 14 '12 08:06

Heshan Perera


2 Answers

This is the hardware serial number. To access it on

  • Android Q (>= SDK 29) android.Manifest.permission.READ_PRIVILEGED_PHONE_STATE is required. Only system apps can require this permission. If the calling package is the device or profile owner then the READ_PHONE_STATE permission suffices.

  • Android 8 and later (>= SDK 26) use android.os.Build.getSerial() which requires the dangerous permission READ_PHONE_STATE. Using android.os.Build.SERIAL returns android.os.Build.UNKNOWN.

  • Android 7.1 and earlier (<= SDK 25) and earlier android.os.Build.SERIAL does return a valid serial.

It's unique for any device. If you are looking for possibilities on how to get/use a unique device id you should read here.

For a solution involving reflection without requiring a permission see this answer.

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thaussma Avatar answered Nov 12 '22 03:11

thaussma


Up to Android 7.1 (SDK 25)

Until Android 7.1 you will get it with:

Build.SERIAL

From Android 8 (SDK 26)

On Android 8 (SDK 26) and above, this field will return UNKNOWN and must be accessed with:

Build.getSerial()

which requires the dangerous permission android.permission.READ_PHONE_STATE.

From Android Q (SDK 29)

Since Android Q using Build.getSerial() gets a bit more complicated by requiring:

android.Manifest.permission.READ_PRIVILEGED_PHONE_STATE (which can only be acquired by system apps), or for the calling package to be the device or profile owner and have the READ_PHONE_STATE permission. This means most apps won't be able to uses this feature. See the Android Q announcement from Google.

See Android SDK reference


Best Practice for Unique Device Identifier

If you just require a unique identifier, it's best to avoid using hardware identifiers as Google continuously tries to make it harder to access them for privacy reasons. You could just generate a UUID.randomUUID().toString(); and save it the first time it needs to be accessed in e.g. shared preferences. Alternatively you could use ANDROID_ID which is a 8 byte long hex string unique to the device, user and (only Android 8+) app installation. For more info on that topic, see Best practices for unique identifiers.

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Patrick Favre Avatar answered Nov 12 '22 04:11

Patrick Favre