Android: can you have a ripple effect whose default state color is transparent?

Question

Something like the following, but it doesn't work. If I switch the drawable color to something like blue, it works.

<ripple xmlns:android="http://schemas.android.com/apk/res/android"     android:color="?android:colorControlHighlight">     <item android:drawable="@android:color/transparent"/> </ripple> 

Answer 1

It's necessary to add a mask:

<ripple xmlns:android="http://schemas.android.com/apk/res/android"     android:color="?android:colorControlHighlight">      <item android:id="@android:id/mask">        <color android:color="@android:color/white" />      </item> </ripple> 

Answer 2

Somehow, the @JMPergar 's answer didn't work for me.

However, I was able to think of this workaround: if a colour behind your transparent button is solid (not a gradient or a speckled picture) - you can use that color as a main button's unpressed one.

<?xml version="1.0" encoding="utf-8"?> <ripple xmlns:android="http://schemas.android.com/apk/res/android"         android:color="@color/profile_transparent_button_pressed"         >      <item>         <shape>             <corners android:radius="@dimen/profile_transparent_button_corner_radius" />             <solid android:color="@color/profile_background" />         </shape>     </item> </ripple> 

where @color/profile_transparent_button_pressed is a colour to highlight a button, and @color/profile_background - the colour of a layout behind this button. It works exactly as expected, but still definitely is a workaround so you go try @JMPergar 's answer first.