Aliasing a template template parameters

Question

Is it possible to use the using keyword for aliasing a template template parameter?

template <template<int> class T>
struct Foo {
    using type = T;
};

Thanks

Answer 1

using (or typedef) always provide an alias for a type, never for an higher-kinded type (template template parameter). What you can do is templatize the alias itself on the int:

template <template<int> class T>
struct Foo {
    template <int X>
    using type = T<X>;
};