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Age (+leap year) calculation in Javascript?

I've read this question but there were many comments which some said it was accurate and some said it wasn't accurate.

Anyway I have this code which calc person's age in Javascript :

 function calculateDiffYearByString(date)
    {
        var cur = new Date();
        var diff = (cur.getTime() - new Date(date)) / (60 * 60 * 24 * 1000);
        return diff / 365.242;
    }

Now , this part var diff = (cur.getTime() - new Date(date)) / (60 * 60 * 24 * 1000); does consider all actual days (24 hr) from the start date till end date including leap year consideration.

It just count days by a 24 hr's groups. my question is about the / 365.242;

when I asked google , it said :

enter image description here

Which is why I devide it with 365.242.

but I think i'm wrong. becuase (IMHO) the .242 part is regarding the leap year. so I think I'm afraid the leap year is considered in the overall calculation twice ..

Am I wrong? does my calculation is 100% correct ?

like image 823
Royi Namir Avatar asked May 08 '13 08:05

Royi Namir


2 Answers

The calculation is not correct, because of the assumption that a year is 365.242 days.

A year is by average 365.242 days, but there is no actual year that is 365.242 days. A year is either exactly 365 or 366 days (ignoring the small detail that there are some years that have leap seconds.)

To calculate the age as fractional years exactly, you would have to calculate the whole number of years up to the last birthday, and then calculate the fraction for the current year based on how many days the current year has.


You can use code like this to calculate the exact age in years:

function isLeapYear(year) {
    var d = new Date(year, 1, 28);
    d.setDate(d.getDate() + 1);
    return d.getMonth() == 1;
}

function getAge(date) {
    var d = new Date(date), now = new Date();
    var years = now.getFullYear() - d.getFullYear();
    d.setFullYear(d.getFullYear() + years);
    if (d > now) {
        years--;
        d.setFullYear(d.getFullYear() - 1);
    }
    var days = (now.getTime() - d.getTime()) / (3600 * 24 * 1000);
    return years + days / (isLeapYear(now.getFullYear()) ? 366 : 365);
}

var date = '1685-03-21';

alert(getAge(date) + ' years');

Demo: http://jsfiddle.net/Guffa/yMxck/

(Note: the days is also a fractional value, so it will calculate the age down to the exact millisecond. If you want whole days, you would add a Math.floor around the calculation for the days variable.)

like image 83
Guffa Avatar answered Sep 29 '22 05:09

Guffa


Your diff calculation will give you the number of days between the two dates. It will take into account leap years, so over exactly 4 years it will yield (365 * 4) + 1 days.

It will also count partial days so if the date parameter is noon yesterday and today it is 6am then diff will be 0.75.

How you convert from days to years is up to you. Using 365, 365.242, or 365.25 days per year all are reasonable in the abstract. However, since you are calculating people's ages according to their birthdays, I would do it like this http://jsfiddle.net/OldPro/hKyBM/ :

function noon(date) {
    // normalize date to noon that day
    return new Date(date.getFullYear(), date.getMonth(), date.getDate(), 12, 0, 0, 0);
}

// Takes a Date
function getAge(date) {
    var now = noon(new Date()),
        birthday = noon(date),
        thisBirthday = new Date(birthday),
        prevBirthday,
        nextBirthday,
        years,
        partYear,
        msInYear;
    thisBirthday.setFullYear(now.getFullYear());

    if (thisBirthday > now) { // not reached birthday this year
        nextBirthday = thisBirthday;
        prevBirthday = new Date(thisBirthday);
        prevBirthday.setFullYear(now.getFullYear() - 1);
    }
    else {
        nextBirthday = new Date(thisBirthday);
        nextBirthday.setFullYear(now.getFullYear() + 1);
        prevBirthday = thisBirthday;
    }
    years = prevBirthday.getFullYear() - birthday.getFullYear();
    msInYear = nextBirthday - prevBirthday;
    partYear = (now - prevBirthday) / msInYear;

    return years + partYear
}

In other words, I compute the fractional year as number of days since the last birthday divided by the number of days between the previous birthday and the next birthday. I think that is how most people think of birthdays and years.

Note: You can get into trouble with timezones when converting date strings to Dates. Short ISO 8601 dates like '2013-05-14' are interpreted as midnight UTC which makes that date May 13, not May 14 in the US and everywhere else with negative UTC offsets. So be careful.

like image 27
Old Pro Avatar answered Sep 29 '22 03:09

Old Pro