Adjust Single Value within Tensor -- TensorFlow

Question

I feel embarrassed asking this, but how do you adjust a single value within a tensor? Suppose you want to add '1' to only one value within your tensor?

Doing it by indexing doesn't work:

TypeError: 'Tensor' object does not support item assignment 

One approach would be to build an identically shaped tensor of 0's. And then adjusting a 1 at the position you want. Then you would add the two tensors together. Again this runs into the same problem as before.

I've read through the API docs several times and can't seem to figure out how to do this. Thanks in advance!

Answer 1

UPDATE: TensorFlow 1.0 includes a tf.scatter_nd() operator, which can be used to create delta below without creating a tf.SparseTensor.

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This is actually surprisingly tricky with the existing ops! Perhaps somebody can suggest a nicer way to wrap up the following, but here's one way to do it.

Let's say you have a tf.constant() tensor:

c = tf.constant([[0.0, 0.0, 0.0],                  [0.0, 0.0, 0.0],                  [0.0, 0.0, 0.0]]) 

...and you want to add 1.0 at location [1, 1]. One way you could do this is to define a tf.SparseTensor, delta, representing the change:

indices = [[1, 1]]  # A list of coordinates to update.  values = [1.0]  # A list of values corresponding to the respective                 # coordinate in indices.  shape = [3, 3]  # The shape of the corresponding dense tensor, same as `c`.  delta = tf.SparseTensor(indices, values, shape) 

Then you can use the tf.sparse_tensor_to_dense() op to make a dense tensor from delta and add it to c:

result = c + tf.sparse_tensor_to_dense(delta)  sess = tf.Session() sess.run(result) # ==> array([[ 0.,  0.,  0.], #            [ 0.,  1.,  0.], #            [ 0.,  0.,  0.]], dtype=float32) 

Answer 2

How about tf.scatter_update(ref, indices, updates) or tf.scatter_add(ref, indices, updates)?

ref[indices[...], :] = updates ref[indices[...], :] += updates 

See this.