Consider the following code :
template<bool AddMembers> class MyClass { public: void myFunction(); template<class = typename std::enable_if<AddMembers>::type> void addedFunction(); protected: double myVariable; /* SOMETHING */ addedVariable; };
In this code, the template parameter AddMembers
allow to add a function to the class when it's true
. To do that, we use an std::enable_if
.
My question is : is the same possible (maybe with a trick) for data members variable ? (in a such way that MyClass<false>
will have 1 data member (myVariable
) and MyClass<true>
will have 2 data members (myVariable
and addedVariable
) ?
A conditional base class may be used:
struct BaseWithVariable { int addedVariable; }; struct BaseWithoutVariable { }; template <bool AddMembers> class MyClass : std::conditional<AddMembers, BaseWithVariable, BaseWithoutVariable>::type { // etc. };
First off, your code just won't compile for MyClass<false>
. The enable_if
trait is useful for deduced arguments, not for class template arguments.
Second, here's how you could control members:
template <bool> struct Members { }; template <> struct Members<true> { int x; }; template <bool B> struct Foo : Members<B> { double y; };
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