Adding hexa values in C#

Question

In my system,i need to add 2 Hexa values.So, how can i add hexa values in C#? And i also want to know the max length of Hexa values and which Instance hold these values.

Answer 1

For 64 character numbers, you need to use the BigInteger type of .Net 4, the normal types are too small:

BigInteger bi1 = BigInteger.Parse("123456789012345678901234567890123456789012345678901234567890abc5", NumberStyles.HexNumber);
BigInteger bi2 = BigInteger.Parse("123456789012345678901234567890123456789012345678901234567890abc1", NumberStyles.HexNumber);
BigInteger sum = BigInteger.Add(bi1, bi2);
Console.WriteLine("{0:x}", sum); //or sum.ToString("x")

(remember adding a reference to System.Numerics)

Answer 2

  int a = 0x2;
  int b = 0x5f;
  int value = a + b; //adding hex values

  string maxHex = int.MaxValue.ToString("x"); //maximum range of hex value as int

Answer 3

Hexadecimal values are just plain old integers (after all, the number 10 in base ten and the number A in hexadecimal are the same thing, just viewed differently); if you need to convert one to a hex string, use: value.ToString("X"), where value is an integral type (like int).