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Adding a simple lm trend line to a ggplot boxplot

When adding a linear model trend line to a boxplot using standard R graphics I use:

boxplot(iris[,2]~iris[,1],col="LightBlue",main="Quartile1 (Rare)")
modelQ1<-lm(iris[,2]~iris[,1])
abline(modelQ1,lwd=2)

However, when using this in ggplot2:

a <- ggplot(iris,aes(factor(iris[,1]),iris[,2]))
a + geom_boxplot() +
geom_smooth(method = "lm", se=FALSE, color="black", formula=iris[,2]~iris[,1])

I get the following error:

geom_smooth: Only one unique x value each group.Maybe you want aes(group = 1)?

And the line does not appear on my plot.

The models used in both of these scenarios are identical. If anyone could point out where I'm going wrong, that would be great.

EDIT: Used the iris dataset as an example.

like image 437
JPD Avatar asked Jun 06 '12 08:06

JPD


2 Answers

The error message is pretty much self-explanatory: Add aes(group=1) to geom_smooth:

ggplot(iris, aes(factor(Sepal.Length), Sepal.Width)) +
  geom_boxplot() +
  geom_smooth(method = "lm", se=FALSE, color="black", aes(group=1))

enter image description here

like image 83
Andrie Avatar answered Oct 21 '22 14:10

Andrie


FYI, this error can also be encountered (and fixed) using the simple qplot interface to ggplot2

The error message is not explanatory enough for a few people at least :-). In this case, the key is to include only the contents of the suggested aesthetic

library(ggplot2)
qplot(factor(Sepal.Length), Sepal.Width, geom = c("smooth"), data= iris)
# error, needs aes(group=1)
qplot(factor(Sepal.Length), Sepal.Width, geom = c("smooth"), group = 1, data= iris)
like image 29
tim Avatar answered Oct 21 '22 14:10

tim