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I have a file as below:
line1 line2 line3 And I want to get:
prefixline1 prefixline2 prefixline3 I could write a Ruby script, but it is better if I do not need to.
prefix will contain /. It is a path, /opt/workdir/ for example.
844
The ^ character is what instructs the sed command to add a character to the beginning of each line. Here's the syntax for adding a space to the beginning of each line using sed . Alternatively, use the -i option with the sed command to edit a file in place.
† By default xargs will pass multiple lines of input to a single command, appending them all to its argument list. But specifying -I % makes xargs put the input at the specified place in the command, and only put one line there at a time, running echo as many times as required.
# If you want to edit the file in-place sed -i -e 's/^/prefix/' file # If you want to create a new file sed -e 's/^/prefix/' file > file.new If prefix contains /, you can use any other character not in prefix, or escape the /, so the sed command becomes
's#^#/opt/workdir#' # or 's/^/\/opt\/workdir/' 
awk '$0="prefix"$0' file > new_file In awk the default action is '{print $0}' (i.e. print the whole line), so the above is equivalent to:
awk '{print "prefix"$0}' file > new_file With Perl (in place replacement):
perl -pi 's/^/prefix/' file If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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