I have to render some templates and send the HTML block to SendGrid for email substitution. So, unfortunately, I am doing some rendering in model like this:
view = ActionView::Base.new(Rails.configuration.paths["app/views"].first)
view.render(:partial => template_name)
Even if I added:
view.extend Rails.application.routes.url_helpers
view.extend ActionView::Helpers::UrlHelper
view.extend ApplicationHelper
The partial don't have access to URL Helpers like url_for unless I explicit define the module like in the following:
Rails.application.routes.url_helpers.edit_user_url(user, :host => Rails.application.config.action_mailer.default_url_options[:host])
Is there a cleaner way to use URL Helper in templates called from models?
In Rails 5, it is simple:
ApplicationController.render partial: 'my/partial'
It will have all your helpers loaded
more info: https://evilmartians.com/chronicles/new-feature-in-rails-5-render-views-outside-of-actions
A workaround I found is to pass the url_helpers
as part of the locals
:
url = Rails.application.routes.url_helpers
view = ActionView::Base.new(Rails.configuration.paths['app/views'].first)
view.render(partial: template, locals: locals.merge(url: url))
and then in the view:
<%= url.thing_path %>
Also note you must to configure your default_url_options
with:
# config/environments/production.rb
config.after_initialize do
Rails.application.routes.default_url_options = { host: 'production.server.com' }
end
# config/environments/development.rb
config.after_initialize do
Rails.application.routes.default_url_options = { host: 'localhost', port: 3000 }
end
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