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Accessing struct fields inside a map value (without copying)

Tags:

go

Assuming the following

type User struct {     name string }  users := make(map[int]User)  users[5] = User{"Steve"} 

Why isn't it possible to access the struct instance now stored in the map?

users[5].name = "Mark" 

Can anyone shed some light into how to access the map-stored struct, or the logic behind why it's not possible?

Notes

I know that you can achieve this by making a copy of the struct, changing the copy, and copying back into the map -- but that's a costly copy operation.

I also know this can be done by storing struct pointers in my map, but I don't want to do that either.

like image 954
gwelter Avatar asked Jul 03 '13 01:07

gwelter


1 Answers

The fundamental problem is that you can't take the address of an item within a map. You might think the compiler would re-arrange users[5].name = "Mark" into this

(&users[5]).name = "Mark" 

But that doesn't compile, giving this error

cannot take the address of users[5] 

This gives the maps the freedom to re-order things at will to use memory efficiently.

The only way to change something explicitly in a map is to assign value to it, i.e.

t := users[5] t.name = "Mark" users[5] = t 

So I think you either have to live with the copy above or live with storing pointers in your map. Storing pointers have the disadvantage of using more memory and more memory allocations, which may outweigh the copying way above - only you and your application can tell that.

A third alternative is to use a slice - your original syntax works perfectly if you change users := make(map[int]User) to users := make([]User, 10)

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Nick Craig-Wood Avatar answered Oct 13 '22 01:10

Nick Craig-Wood