Accessing base class's method with derived class's object which has a method of same name

Question

when accessing foo() of "base" using derived class's object.

#include <iostream>

class  base
{
      public:
      void foo()
     {
        std::cout<<"\nHello from foo\n";
     }
};

class derived : public base
{
     public:
     void foo(int k)
     {
        std::cout<<"\nHello from foo with value = "<<k<<"\n";
     }
};
int main()
{
      derived d;
      d.foo();//error:no matching for derived::foo()
      d.foo(10);

}

how to access base class method having a method of same name in derived class. the error generated has been shown. i apologize if i am not clear but i feel i have made myself clear as water. thanks in advance.

Answer 1

You could add using base::foo to your derived class:

class derived : public base
{
public:
     using base::foo;
     void foo(int k)
     {
        std::cout<<"\nHello from foo with value = "<<k<<"\n";
     }
};

Edit: The answer for this question explains why your base::foo() isn't directly usable from derived without the using declaration.

Answer 2

d.base::foo();