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Access resources in another osgi bundle?

I have created two OSGI bundles A and B using the eclipse Plug-in project wizard (using eclipse Helios).

In the manifest file of bundle B I have added bundle A as a dependency. Further I have exported the packages in A so they are visible for B. I also have a .properties file in bundle A that I would like to make visible for bundle B. In the build.properties pane in bundle A I have specified:

source.. = src/
bin.includes = META-INF/,\
               .,\
               bundle_A.properties

Now in bundle B I try to load the .properties file using:

  private Properties loadProperties() {
    Properties properties = new Properties();
    InputStream istream = this.getClass().getClassLoader().getResourceAsStream(
        "bundle_A.properties");
    try {
      properties.load(istream);
    } catch (IOException e) {
      logger.error("Properties file not found!", e);
    }
    return properties;
  }

But that gives a nullpointer exception (the file is not found on the classpath).

Is it possible to export resources from bundle A (just like when you export packages) or somehow access the file in A from B in another way (accessing the classloader for bundle A from bundle B)?

like image 259
u123 Avatar asked Aug 19 '10 14:08

u123


2 Answers

The getEntry(String) method on Bundle is intended for this purpose. You can use it to load any resource from any bundle. Also see the methods findEntries() and getEntryPaths() if you don't know the exact path to the resource inside the bundle.

There is no need to get hold of the bundle's classloader to do this.

like image 77
Neil Bartlett Avatar answered Sep 27 '22 22:09

Neil Bartlett


If you're writing an Eclipse plug-in you could try something like:

Bundle bundle = Platform.getBundle("your.plugin.id");

Path path = new Path("path/to/a/file.type");

URL fileURL = Platform.find(bundle, path);

InputStream in = fileURL.openStream();
like image 34
Johannes Wachter Avatar answered Sep 27 '22 23:09

Johannes Wachter