I am trying to find the most efficient way of displaying an image using django's template context loader. I have a static dir within my app which contains the image 'victoryDance.gif' and an empty static root dir at the project level (with settings.py
). assuming the paths within my urls.py
and settings.py
files are correct. what is the best view?
from django.shortcuts import HttpResponse
from django.conf import settings
from django.template import RequestContext, Template, Context
def image1(request): # good because only the required context is rendered
html = Template('<img src="{{ STATIC_URL }}victoryDance.gif" alt="Hi!" />')
ctx = { 'STATIC_URL':settings.STATIC_URL}
return HttpResponse(html.render(Context(ctx)))
def image2(request): # good because you don't have to explicitly define STATIC_URL
html = Template('<img src="{{ STATIC_URL }}victoryDance.gif" alt="Hi!" />')
return HttpResponse(html.render(RequestContext(request)))
def image3(request): # This allows you to load STATIC_URL selectively from the template end
html = Template('{% load static %}<img src="{% static "victoryDance.gif" %}" />')
return HttpResponse(html.render(Context(request)))
def image4(request): # same pros as image3
html = Template('{% load static %} <img src="{% get_static_prefix %}victoryDance.gif" %}" />')
return HttpResponse(html.render(Context(request)))
def image5(request):
html = Template('{% load static %} {% get_static_prefix as STATIC_PREFIX %} <img src="{{ STATIC_PREFIX }}victoryDance.gif" alt="Hi!" />')
return HttpResponse(html.render(Context(request)))
thanks for answers These views all work!
How you specify the location of an image in Django is in between {% %}. In between these brackets, you specify static 'images\\Python. png', where Python is the image you want to display which is inside of the images directory in the static directory you create for the current app you are in.
render() Combines a given template with a given context dictionary and returns an HttpResponse object with that rendered text. Django does not provide a shortcut function which returns a TemplateResponse because the constructor of TemplateResponse offers the same level of convenience as render() .
Configuring static files Make sure that django.contrib.staticfiles is included in your INSTALLED_APPS . In your templates, use the static template tag to build the URL for the given relative path using the configured STATICFILES_STORAGE . Store your static files in a folder called static in your app.
If you need to render an image read a bit here http://www.djangobook.com/en/1.0/chapter11/ and use your version of the following code:
For django version <= 1.5:
from django.http import HttpResponse
def my_image(request):
image_data = open("/path/to/my/image.png", "rb").read()
return HttpResponse(image_data, mimetype="image/png")
For django 1.5+ mimetype
was replaced by content_type
(so happy I'm not working with django anymore):
from django.http import HttpResponse
def my_image(request):
image_data = open("/path/to/my/image.png", "rb").read()
return HttpResponse(image_data, content_type="image/png")
Also there's a better way of doing things!
Else, if you need a efficient template engine use Jinja2
Else, if you are using Django's templating system, from my knowledge you don't need to define STATIC_URL as it is served to your templates by the "static" context preprocessor:
TEMPLATE_CONTEXT_PROCESSORS = (
'django.contrib.auth.context_processors.auth',
'django.core.context_processors.debug',
'django.core.context_processors.i18n',
'django.core.context_processors.static',
'django.core.context_processors.media',
'django.core.context_processors.request',
'django.contrib.messages.context_processors.messages',
)
In your last example (image5) you should use {{ STATIC_PREFIX }}
instead of {% STATIC_PREFIX %}
STATIC_PREFIX
is variable, not a tag
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