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I have a dictionary like this:
A = {'a':10, 'b':843, 'c': 39,.....} I want to get the 5 maximum values of this dict and store a new dict with this. To get the maximum value I did:
max(A.iteritems(), key=operator.itemgetter(1))[0:] Perhaps it is an easy task, but I am stuck on it for a long time. Please help!!!
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By using max() and dict. get() method we can easily get the Key with maximum value in a dictionary. To obtain the maximum value from the dictionary we can use the in-built max() function. In this example, we can use iterable and dict to get the key paired with the maximum value.
The simplest way to get the max value of a Python dictionary is to use the max() function. The function allows us to get the maximum value of any iterable.
You can add as many items as you like.
It will not display the output because the computer ran out of memory before reaching 2^27. So there is no size limitation in the dictionary.
No need to use iteritems and itemgetter. The dict's own get method works fine.
max(A, key=A.get) Similarly for sorting:
sorted(A, key=A.get, reverse=True)[:5] Finally, if the dict size is unbounded, using a heap will eventually be faster than a full sort.
import heapq heapq.nlargest(5, A, key=A.get) For more information, have a look at the heapq documentation.
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You are close. You can sort the list using sorted [docs] and take the first five elements:
newA = dict(sorted(A.iteritems(), key=operator.itemgetter(1), reverse=True)[:5]) See also: Python Sorting HowTo
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