zipWithIndex from 1 instead of 0

Question

If I have a list and zipWithIndex

val list = List('a', 'b', 'c')
val ziplist = List.zipWithIndex
// List[(int, int)] = List(('a', 0), ('b', 1), ('c', 2))

If I want to index from 1 instead of 0, is there a smarter way than my current:

val ziplist = List.zipWithIndex.map( ele => (ele._1, ele._2 + 1))

Hope you guys can help!

Described in the summarization

Answer 1

You could use LazyList.from(1) to generate indexes:

List('a', 'b', 'c').zip(LazyList.from(1)) // List((a,1), (b,2), (c,3))

If you're using Scala older than 2.13, you'd need to use Stream instead of LazyList:

List('a', 'b', 'c').zip(Stream.from(1)) // List((a,1), (b,2), (c,3))

Answer 2

You can try this:

val ziplist = list zip (Stream from 1)