zip file and avoid directory structure

Question

I have a Python script that zips a file (new.txt):

tofile =  "/root/files/result/"+file targetzipfile = new.zip # This is how I want my zip to look like zf = zipfile.ZipFile(targetzipfile, mode='w') try:     #adding to archive     zf.write(tofile) finally:     zf.close() 

When I do this I get the zip file. But when I try to unzip the file I get the text file inside of a series of directories corresponding to the path of the file i.e I see a folder called root in the result directory and more directories within it, i.e. I have

/root/files/result/new.zip 

and when I unzip new.zip I have a directory structure that looks like

/root/files/result/root/files/result/new.txt 

Is there a way I can zip such that when I unzip I only get new.txt?

In other words I have /root/files/result/new.zip and when I unzip new.zip, it should look like

/root/files/results/new.txt 

Answer 1

The zipfile.write() method takes an optional arcname argument that specifies what the name of the file should be inside the zipfile

I think you need to do a modification for the destination, otherwise it will duplicate the directory. Use :arcname to avoid it. try like this:

import os import zipfile  def zip(src, dst):     zf = zipfile.ZipFile("%s.zip" % (dst), "w", zipfile.ZIP_DEFLATED)     abs_src = os.path.abspath(src)     for dirname, subdirs, files in os.walk(src):         for filename in files:             absname = os.path.abspath(os.path.join(dirname, filename))             arcname = absname[len(abs_src) + 1:]             print 'zipping %s as %s' % (os.path.join(dirname, filename),                                         arcname)             zf.write(absname, arcname)     zf.close()  zip("src", "dst")