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Using Initializer List. int arr[] = { 1, 1, 1, 1, 1 }; The array will be initialized to 0 if we provide the empty initializer list or just specify 0 in the initializer list.
The initializer can even have no values, just the braces: int baz [5] = { }; This creates an array of five int values, each initialized with a value of zero: But, the elements in an array can be explicitly initialized to specific values when it is declared, by enclosing those initial values in braces {}.
zero-initialization – Applied to static and thread-local variables before any other initialization. If T is scalar (arithmetic, pointer, enum), it is initialized from 0 ; if it's a class type, all base classes and data members are zero-initialized; if it's an array, each element is zero-initialized.
Member initializer list is the place where non-default initialization of these objects can be specified. For bases and non-static data members that cannot be default-initialized, such as members of reference and const-qualified types, member initializers must be specified.
I have a class with an array member that I would like to initialize to all zeros.
class X { private: int m_array[10]; }; For a local variable, there is a straightforward way to zero-initialize (see here):
int myArray[10] = {}; Also, the class member m_array clearly needs to be initialized, as default-initializing ints will just leave random garbage, as explained here.
However, I can see two ways of doing this for a member array:
With parentheses:
public: X() : m_array() {} With braces:
public: X() : m_array{} {} Are both correct? Is there any difference between the two in C++11?
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