XOR higher 32 bits with lower 32 bits in a 64 bit number

Question

In a 64 bit number How to XOR Higher order 32 bits with lower order 32 bits. Thank you

Answer 1

(v & 0xffffffff) ^ ((v >> 32) & 0xffffffff)

Answer 2

Just for kicks, here's another solution. The one given already is probably the way to go.

uint32_t* number32;
uint64_t number64 = 0xffff1111ffffffff;
uint32_t xorValue;

number32 = (uint32_t*)&number64;
xorValue = number32[0]^number32[1];