xml.parsers.expat.ExpatError on parsing XML

Question

I am trying to parse XML with Python but not getting very far. I think it's due to wrong XML tree this API returns.

So this is what is returned by the GET request:

<codigo>3</codigo><valor></valor><operador>Dummy</operador>

The GET request goes here:

http://69.36.9.147:8090/clientes/SMS_API_OUT.jsp?codigo=ABCDEFGH&cliente=XX

This is the Python code I am using without any luck:

import urllib
from xml.dom import minidom

url = urllib.urlopen('http://69.36.9.147:8090/clientes/SMS_API_OUT.jsp?codigo=ABCDEFGH&cliente=XX')
xml = minidom.parse(url)
code = doc.getElementsByTagName('codigo')

print code[0].data

And this is the response I get:

xml.parsers.expat.ExpatError: junk after document element: line 1, column 18

What I need to do is retrieve the value inside the <codigo> element and place it in a variable (same for the others).

Answer 1

The main problem here is that the XML code being returned by that service doesn't include a root node, which is invalid. I fixed this by simply wrapping the output in a <root> node.

import urllib
from xml.etree import ElementTree

url = 'http://69.36.9.147:8090/clientes/SMS_API_OUT.jsp?codigo=ABCDEFGH&cliente=XX'
xmldata = '<root>' + urllib.urlopen(url).read() + '</root>'
tree = ElementTree.fromstring(xmldata)
codigo = tree.find('codigo').text

print codigo

You can use whatever parser you wish, but here I used ElementTree to get the value.

Answer 2

An XML document consists of one top level document element, and then multiple subelements. Your XML fragment contains multiple top level elements, which is not permitted by the XML standard.

Try returning something like:

<result><codigo>3</codigo><valor></valor><operador>Dummy</operador></result>

I have wrapped the entire response in a <result> tag.