Im trying to deserialize the response from this simple web service
Im using the following code:
WebRequest request = WebRequest.Create("http://inb374.jelastic.tsukaeru.net:8080/VodafoneDB/webresources/vodafone/04111111");
WebResponse ws = request.GetResponse();
XmlSerializer s = new XmlSerializer(typeof(string));
string reponse = (string)s.Deserialize(ws.GetResponseStream());
Declaring XmlSerializer as
XmlSerializer s = new XmlSerializer(typeof(string),new XmlRootAttribute("response"));
is enough.
You want to deserialize the XML and treat it as a fragment.
There's a very straightforward workaround available here. I've modified it for your scenario:
var webRequest = WebRequest.Create("http://inb374.jelastic.tsukaeru.net:8080/VodafoneDB/webresources/vodafone/04111111");
using (var webResponse = webRequest.GetResponse())
using (var responseStream = webResponse.GetResponseStream())
{
var rootAttribute = new XmlRootAttribute();
rootAttribute.ElementName = "response";
rootAttribute.IsNullable = true;
var xmlSerializer = new XmlSerializer(typeof (string), rootAttribute);
var response = (string) xmlSerializer.Deserialize(responseStream);
}
I had the same error with Deserialize "xml string with 2 namespaces declared" into object.
<?xml version="1.0" encoding="utf-8"?>
<vcs-device:errorNotification xmlns:vcs-pos="http://abc" xmlns:vcs-device="http://def">
<errorText>Can't get PAN</errorText>
</vcs-device:errorNotification>
[XmlRoot(ElementName = "errorNotification", Namespace = "http://def")]
public class ErrorNotification
{
[XmlAttribute(AttributeName = "vcs-pos", Namespace = "http://www.w3.org/2000/xmlns/")]
public string VcsPosNamespace { get; set; }
[XmlAttribute(AttributeName = "vcs-device", Namespace = "http://www.w3.org/2000/xmlns/")]
public string VcsDeviceNamespace { get; set; }
[XmlElement(ElementName = "errorText", Namespace = "")]
public string ErrorText { get; set; }
}
By adding field with [XmlAttribute] into ErrorNotification class deserialization works.
public static T Deserialize<T>(string xml)
{
var serializer = new XmlSerializer(typeof(T));
using (TextReader reader = new StringReader(xml))
{
return (T)serializer.Deserialize(reader);
}
}
var obj = Deserialize<ErrorNotification>(xml);
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