I'm reading xls file using xlrd. The problem is, when xlrd reading value like this "12/09/2012", i get result like this "xldate:41252.0". When I use xlrd.xldate_as_tuple, i get this result:
(2016, 12, 10, 0, 0, 0)
My code:
curr_row = -1
while curr_row < num_rows:
curr_row += 1
row = worksheet.row(curr_row)
for x in xrange(num_cols):
field_type = worksheet.cell_type(curr_row, x)
if field_type == 3: # this is date
field_value = worksheet.cell_value(curr_row, x)
print worksheet.cell(curr_row, x).value
print xlrd.xldate_as_tuple(field_value, 1)
Result:
41252.0
(2016, 12, 10, 0, 0, 0)
Both results are wrong for me. How can i get original cell value "12/09/2012" using xlrd ?
To check if it is empty: simply write if cell_vel == ''
openpyxl has a broader approval, being mentioned in *7 company stacks & 7 developers stacks; compared to xlrd, which is listed in 5 company stacks and 6 developer stacks.
xlrd is a library for reading data and formatting information from Excel files in the historical . xls format. This library will no longer read anything other than . xls files.
According to the docstring, you should pass your workbook's datemode to xldate_as_tuple
as a second parameter:
from datetime import datetime
import xlrd
book = xlrd.open_workbook("test.xls")
sheet = book.sheet_by_index(0)
a1 = sheet.cell_value(rowx=0, colx=0)
print a1 # prints 41252.0
print xlrd.xldate_as_tuple(a1, 1) # prints (2016, 12, 10, 0, 0, 0)
a1_tuple = xlrd.xldate_as_tuple(a1, book.datemode)
print a1_tuple # prints (2012, 12, 9, 0, 0, 0)
a1_datetime = datetime(*a1_tuple)
print a1_datetime.strftime("%m/%d/%Y") # prints 12/09/2012
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With