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zgrep -i XXX XXX | grep -o "RID=[0-9|A-Z]*" |
uniq | cut -d "=" -f2 |
xargs -0 -I string echo "RequestID="string
My output is
RequestID=121212112
8127127128
8129129812
But my requirement is to have the request ID prefixed before all the output. Any help is appreciated
320
Combine xargs with grepUse xargs with the grep command to search for a string in the list of files provided by the find command. The example above searched for all the files with the . txt extension and piped them to xargs , which then executed the grep command on them.
xargs (short for "extended arguments") is a command on Unix and most Unix-like operating systems used to build and execute commands from standard input. It converts input from standard input into arguments to a command.
The xargs command is used in a UNIX shell to convert input from standard input into arguments to a command. In other words, through the use of xargs the output of a command is used as the input of another command.
xargs reads items from the standard input, delimited by blanks (which can be protected with double or single quotes or a backslash) or newlines, and executes the command (default is echo) one or more times with any initial-arguments followed by items read from standard input.
I had a similar task and this worked for me. It might be what you are looking for:zgrep -i XXX XXX | grep -o "RID=[0-9|A-Z]*" |
uniq | cut -d "=" -f2 |
xargs -I {} echo "RequestID="{}
178
Try -n option of xargs.
-n max-args
Use at most max-args arguments per command line. Fewer than max-args arguments will be used if the size (see the -s option) is exceeded, unless the -x option is given, in which case xargs will exit.
Example:
$ echo -e '1\n2' | xargs echo 'str ='
str = 1 2
$ echo -e '1\n2' | xargs -n 1 echo 'str ='
str = 1
str = 2
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