Wrong result from the conversion in an array

Question

Let's say that I have

char number[2] = "2";

In my code I get number 2 as a string that's why i have char. Now with the usage of atoi I convert this char to int

int conv_number;
conv_number = atoi(number);
printf("Result : %d\n", conv_number);

which returns me Result : 2. Now I want to put this value in an array and print the result of the array.So I wrote

int array[] = {conv_number};
printf("%d\n",array);

Unfortunately my result is not 2 but -1096772864. What am I missing;

Answer 1

You're missing that your array is int[] not int, which is the expected second argument for printf when you use the digit format parameter %d.

Use printf("%d\n",array[0]) instead, since you want to access the first value in your array.

Further explanation

In this circumstances array in your printf expression behaves as int*. You would get the same result if you were to use printf("%d\n",&array[0]), aka the address of the first element. Note that if you're really interested in the address use the %p format specifier instead.