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Writing my own init executable

I wanted to create my own init and some Linux fun for a snowy weekend. I know, kernel boots with rootfs and gives the flow to /sbin/init after some driver loading and disk mounting. I downloaded ubuntu cloud image and tried direct kernel boot with kvm as follows:

kvm -m 1G -nographic -kernel vmlinuz-3.19.0-32-generic -initrd initrd.img-3.19.0-32-generic -append "console=ttyS0 root=/dev/sda1 rw init=/myinit" -hda mydisk.img 

It works somewhat fine with trusty-server-cloudimg-amd64-disk1.img (if you don't mind hanging at cloud-init), then I proceeded to copy it and delete its content.

modprobe nbd
qemu-nbd -c /dev/nbd0 mydisk.img 
fdisk -l /dev/nbd0 # confirm partition
mount /dev/nbd0p1 disk/
# Delete all files with myinit.c and myinit

And here is my magical init:

int main(){
    printf("Welcome to my kernel\n");
    printf("Welcome to my kernel\n");
    printf("Welcome to my kernel\n");
    while(1);
}

I compile it with gcc -static myinit.c -o myinit. However a kernel panic occurs because of my init. I verified it by renaming myinit to myinit2 and kernel could not find it, and it did not crash. I know writing init cannot be as simple as the above, but what are the steps required for it? I am reading upstart source code

Begin: Mounting root file system ... Begin: Running /scripts/local-top ... done.
Begin: Running /scripts/local-premount ... [    1.460164] tsc: Refined TSC clocksource calibration: 2394.558 MHz
[    1.866560] input: ImExPS/2 Generic Explorer Mouse as /devices/platform/i8042/serio1/input/input3
done.
[    6.251763] EXT4-fs (sda1): recovery complete
[    6.253623] EXT4-fs (sda1): mounted filesystem with ordered data mode. Opts: (null)
Begin: Running /scripts/local-bottom ... done.
done.
Begin: Running /scripts/init-bottom ... mount: mounting /dev on /root/dev failed: No such file or directory
done.
mount: mounting /sys on /root/sys failed: No such file or directory
mount: mounting /proc on /root/proc failed: No such file or directory
[    6.299404] Kernel panic - not syncing: Attempted to kill init! exitcode=0x00000200
[    6.299404] 
[    6.300013] CPU: 0 PID: 1 Comm: init Not tainted 3.19.0-32-generic #37~14.04.1-Ubuntu
[    6.300013] Hardware name: QEMU Standard PC (i440FX + PIIX, 1996), BIOS Bochs 01/01/2011
[    6.300013]  ffff88003c118700 ffff88003dee7e38 ffffffff817af41b 00000000000017d6
[    6.300013]  ffffffff81a90be8 ffff88003dee7eb8 ffffffff817a925b ffff88003dee8000
[    6.300013]  ffffffff00000010 ffff88003dee7ec8 ffff88003dee7e68 ffffffff81c5ee20
[    6.300013] Call Trace:
[    6.300013]  [<ffffffff817af41b>] dump_stack+0x45/0x57
[    6.300013]  [<ffffffff817a925b>] panic+0xc1/0x1f5
[    6.300013]  [<ffffffff81077b01>] do_exit+0xa11/0xb00
[    6.300013]  [<ffffffff811ec53c>] ? vfs_write+0x15c/0x1f0
[    6.300013]  [<ffffffff81077c7f>] do_group_exit+0x3f/0xa0
[    6.300013]  [<ffffffff81077cf4>] SyS_exit_group+0x14/0x20
[    6.300013]  [<ffffffff817b6dcd>] system_call_fastpath+0x16/0x1b
[    6.300013] Kernel Offset: 0x0 from 0xffffffff81000000 (relocation range: 0xffffffff80000000-0xffffffffbfffffff)
[    6.300013] drm_kms_helper: panic occurred, switching back to text console
[    6.300013] ---[ end Kernel panic - not syncing: Attempted to kill init! exitcode=0x00000200
[    6.300013] 

I know myinit is completely static:

# ldd disk/myinit
    not a dynamic executable

So it should not depend anything else, I guess. But what am I doing wrong and why is kernel panicking? (Kernel panicks without printfs too)

I am reading sysvinit source (it should be simpler then upstart & systemd & openrc) but its too long, but the main idea of init is to own the processes and it rests in while(1) loop too.

like image 837
Mustafa Avatar asked Feb 06 '16 19:02

Mustafa


1 Answers

Your stdin, stdout and stderr might not be connected when your init starts. It's common to see a sequence similar to the following at the start of an init program:

    int onefd = open("/dev/console", O_RDONLY, 0);
    dup2(onefd, 0); // stdin
    int twofd = open("/dev/console", O_RDWR, 0);
    dup2(twofd, 1); // stdout
    dup2(twofd, 2); // stderr

    if (onefd > 2) close(onefd);
    if (twofd > 2) close(twofd);

This ensures that stdin, stdout and stderr are connected to the system console.

like image 56
davmac Avatar answered Oct 15 '22 19:10

davmac