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Writing a simple equation parser

What sorts of algorithms would be used to do this (as in, this is a string, and I want to find the answer):

((5 + (3 + (7 * 2))) - (8 * 9)) / 72

Say someone wrote that in, how could I deal with so many nested parenthesis?

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jmasterx Avatar asked Jan 03 '11 06:01

jmasterx


2 Answers

You can use Shunting yard algorithm or Reverse Polish Notation, both of them are using stacks to handle this, wiki said it better than me.

From wiki,

While there are tokens to be read:

    Read a token.
    If the token is a number, then add it to the output queue.
    If the token is a function token, then push it onto the stack.
    If the token is a function argument separator (e.g., a comma):

        Until the token at the top of the stack is a left parenthesis, pop operators off the stack onto the output queue. If no left parentheses are encountered, either the separator was misplaced or parentheses were mismatched.

    If the token is an operator, o1, then:

        while there is an operator token, o2, at the top of the stack, and

                either o1 is left-associative and its precedence is less than or equal to that of o2,
                or o1 is right-associative and its precedence is less than that of o2,

            pop o2 off the stack, onto the output queue;

        push o1 onto the stack.

    If the token is a left parenthesis, then push it onto the stack.
    If the token is a right parenthesis:

        Until the token at the top of the stack is a left parenthesis, pop operators off the stack onto the output queue.
        Pop the left parenthesis from the stack, but not onto the output queue.
        If the token at the top of the stack is a function token, pop it onto the output queue.
        If the stack runs out without finding a left parenthesis, then there are mismatched parentheses.

When there are no more tokens to read:

    While there are still operator tokens in the stack:

        If the operator token on the top of the stack is a parenthesis, then there are mismatched parentheses.
        Pop the operator onto the output queue.

Exit.
like image 182
Saeed Amiri Avatar answered Sep 29 '22 09:09

Saeed Amiri


The easiest way to solve this is to implement the Shunting Yard algorithm to convert the expression from infix notation to postfix notation.

It's Easy-with-a-capital-E to evaluate a postfix expression.

The Shunting Yard algorithm can be implemented in under 30 lines of code. You'll also need to tokenize the input (convert the character string into a sequence of operands, operators, and punctuators), but writing a simple state machine to do that is straightforward.

like image 39
James McNellis Avatar answered Sep 29 '22 11:09

James McNellis