write multiple files at a time

Question

I have a file with 196 list in it,and I want to create new 196 output files and write each of the list in a new file, so that I will have 196 output files each containing 1 list of input data Here is the input file:

"['128,129', '116,118', '108,104', '137,141', '157,144', '134,148', '138,114', '131,138', '248,207', '208,247', '246,248', '101,106', '131,115', '119,120', '131,126', '138,137', '132,129']"
"['154,135', '151,147', '236,244', '243,238', '127,127', '125,126', '122,124', '123,126', '127,129', '122,121', '147,134', '126,132', '128,137', '233,222', '222,236', '125,126']"

.....here for eg, I have given only 2 list but total 196 list are present. Output should be:

file 1 :

128,129
116,118
108,104

file2 :

154,135
151,147
236.244

Current code:

fn = open("/home/vidula/Desktop/project/ori_tri/inpt.data","r")
fnew = fn.read()
fs = fnew.split('\n')
for value in fs:
    f = [open("/home/vidula/Desktop/project/ori_tri/input_%i.data" %i,'w') for i in range(len(list_of_files))]
    f.write(value)
    f.close()

Error: list do not attribute write.

Answer 1

Your current code is loading everything into memory, which is quite unnecessary, then it is making a list in a place that is not appropriate, hence your error. Try this:

fn = open("/home/vidula/Desktop/project/ori_tri/inpt.data","r")
for i, line in enumerate(fn):
    f = open("/home/vidula/Desktop/project/ori_tri/input_%i.data" %i,'w')
    f.write(line)
    f.close()

This will just write each line as it was to each file. Look up the enumerate function I used to do the indexing.

Having done this, you will still need to write parsing logic to turn each line into a series of lines...I'm not going to do that for you here, since your original code didn't really have logic for it either.

Answer 2

your f is a list of files, you have to loop through it:

for file in f:
   file.write(value)