Working of SizeOf Function for char Array

Question

void main()
{
   char s[]="\12345s\n";
   printf("%d",sizeof(s));
}

When i compile it it giving 6. I am not geting why it is giving 6 insted of 8. Like {'\1','2','3','4','5','s','\n'}

Please can anybody tell the reason for this, I want some deep and clear explanation. I will be thankful to them.

Answer 1

Because \123 is considered one character, it's an escape sequence (octal). So sizeof calculates 5 characters '\123', '4', '5', 's', '\n', and the ending '\0'.