Could you please explain the difference between "return 0" and "return"? For example:
do_1():
for i in xrange(5):
do_sth()
return 0
do_2():
for i in xrange(5):
do_sth()
return
What is the difference between two functions above?
Depends on usage:
>>> def ret_Nothing():
... return
...
>>> def ret_None():
... return None
...
>>> def ret_0():
... return 0
...
>>> ret_Nothing() == None
True
>>> ret_Nothing() is None # correct way to compare values with None
True
>>> ret_None() is None
True
>>> ret_0() is None
False
>>> ret_0() == 0
True
>>> # and...
>>> repr(ret_Nothing())
'None'
And as mentioned by Tichodroma, 0
is not equal to None
. However, in boolean context, they are both False
:
>>> if ret_0():
... print 'this will not be printed'
... else:
... print '0 is boolean False'
...
0 is boolean False
>>> if ret_None():
... print 'this will not be printed'
... else:
... print 'None is also boolean False'
...
None is also boolean False
More on Boolean context in Python: Truth Value Testing
In Python, every function returns a return value, either implicitly or explicitly.
>>> def foo():
... x = 42
...
>>> def bar():
... return
...
>>> def qux():
... return None
...
>>> def zero():
... return 0
...
>>> print foo()
None
>>> print bar()
None
>>> print qux()
None
>>> print zero()
0
As you can see, foo
, bar
and qux
return exactly the same, the built in constant None
.
foo
returns None
because a return
statement is missing and None
is the default return value if a function doesn't explicitly return a value.
bar
returns None
because it uses a return
statement without an argument, which also defaults to None
.
qux
returns None
because it explicitly does so.
zero
however is entirely different and returns the integer 0
.
If evaluated as booleans, 0
and None
both evaluate to False
, but besides that, they are very different (different types in fact, NoneType
and int
).
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