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What I know about unsigned numerics (unsigned short, int and longs), that It contains positive numbers only, but the following simple program successfully assigned a negative number to an unsigned int:
1 /*
2 * =====================================================================================
3 *
4 * Filename: prog4.c
5 *
6 * =====================================================================================
7 */
8
9 #include <stdio.h>
10
11 int main(void){
12
13 int v1 =0, v2=0;
14 unsigned int sum;
15
16 v1 = 10;
17 v2 = 20;
18
19 sum = v1 - v2;
20
21 printf("The subtraction of %i from %i is %i \n" , v1, v2, sum);
22
23 return 0;
24 }
The output is :
The subtraction of 10 from 20 is -10
222
You simply cannot assign a negative value to an object of an unsigned type. Any such value will be converted to the unsigned type before it's assigned, and the result will always be >= 0.
Unsigned Integers (often called "uints") are just like integers (whole numbers) but have the property that they don't have a + or - sign associated with them. Thus they are always non-negative (zero or positive).
An unsigned integer will never be a negative value, the smallest value it can be is 0 (zero). The values you get are not garbage. Assigning -1 to an unsigned type will give you the maximum value that variable can hold.
Integers: Integers are the set of numbers including all the positive counting numbers, zero as well as all negative counting numbers which count from negative infinity to positive infinity. The set doesn't include fractions and decimals.
%i is the format specifier for a signed integer; you need to use %u to print an unsigned integer.
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