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why []string can not be converted to []interface{} in golang [duplicate]

I found its weird, why []string can not be converted to []interface{} ?

I think it should be possible, because:

  1. they are all slices
  2. every element of []string is string, which of course is interface{}

but in the example below, it will be a compilation error

func f(args ...interface{}){

}
s := []string{"ssd", "rtt"}
f(s...)

why the language can't finish the conversion automatically?

like image 549
zhaozhi Avatar asked Jan 24 '14 05:01

zhaozhi


2 Answers

Because []string and []interface{} have different in-memory layouts. This is obvious when you realise that an interface{} variable needs to know the type of the value it contains.

For a []string slice, the backing array only needs to hold the individual strings. For the []interface{} slice, you've got both type information and the string values (well, pointers to the string values, since a string is larger than a single word of memory). So converting from one type to the other will involve copying the data.

It would be confusing for Go to automatically perform a conversion, since it would make it difficult to reason about code. For example, a function call f(s) could modify the strings in the slice s if it was declared to take a []string argument, but not if it was declared to take a []interface{} argument.

like image 96
James Henstridge Avatar answered Sep 21 '22 11:09

James Henstridge


Slice is basically just a reference to the underlying array, start pointer, length and capacity. So if it would be possible, then consider the following:

sliceOfStrings := []string{"one", "two", "three"}
// prints ONE TWO THREE
for i := range sliceOfStrings {
    fmt.Println(strings.ToUpper(sliceOfStrings[i]))
}

// imagine this is possible
var sliceOfInterface = []interface{}(sliceOfStrings)
// since it's array of interface{} now - we can do anything
// let's put integer into the first position
sliceOfInterface[0] = 1
// sliceOfStrings still points to the same array, and now "one" is replaced by 1
fmt.Println(strings.ToUpper(sliceOfStrings[0])) // BANG!

This issue exists in Java and C#. In practice it happens rarely, but still. Given that in Go there is no automatic type conversions like int32 -> int64 it makes sense that you are forced to create a []interface{} copy if you really want to send []string as []interface{}. This way there can be no surprise - you wrote it explicitly, you know what you're doing. And if function will modify []interface{} - it won't hurt original []string.

like image 36
Kluyg Avatar answered Sep 22 '22 11:09

Kluyg