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Why Nullable type must have struct constraint

Tags:

c#

oop

struct

class Program
{
    static void Main(string[] args)
    {
        Console.WriteLine(SomeFunction<int>()==null);
        var temp = new SomeClass<int>();
        Console.WriteLine(temp.SomeFunction() == null);
        Console.ReadKey();
    }

    static public T? SomeFunction<T>() where T : struct
    {
        return null;
    }

    public class SomeClass<T> where T : struct 
    {
        public T? SomeFunction()
        {
            return null;
        }
    }
}

In the above example, why does a nullable type need the struct constraint?
I don't understand why struct is the right syntax and not object or class.

like image 807
Gal Katzir Avatar asked Aug 15 '26 18:08

Gal Katzir


1 Answers

Because Nullable<T> (or T?) also restricts T to be a struct.

So, for SomeFunction<T>'s generic type parameter T to fulfill Nullable<T>'s requirements, SomeFunction<T> must also declare the same constraints.

Here's another example of how constraints must be propagated:

interface ISomeInterface { }
class MyClass<T> where T: ISomeInterface { }

class Program
{
    //MyClass's constaints must be "re-declared" here
    public MyClass<T> SomeFunction<T>() where T : ISomeInterface
    {
    }
}

And why does Nullable<T> do that? Because a nullable reference type would make no sense. Refence types are already nullable.

like image 197
dcastro Avatar answered Aug 18 '26 06:08

dcastro



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