I am trying to modify a copied array without changing the original one. This is what I've tried, by using slice()
method, but it doesn't work as expected:
//toFill holds the values I want to add into an array named secondArr,
//replace every empty sting within secondArr with 0
var toFill = [0, 0, 0, 0];
var mainArr = [
[" ", 1, 1, 1],
[" ", 1, 1, 1],
[" ", 1, 1, 1],
[" ", 1, 1, 1]
];
var secondArr = mainArr.slice(0,4);
//this function returns a 1D array, stores the indices of all empty strings within an array
function findBlankSpaces(secondArr) {
var emptyIndices = [];
var innerArrLen = secondArr.length;
var outterArrLen = secondArr[0].length;
for (var i = 0; i < innerArrLen; i++) {
for (var j = 0; j < outterArrLen; j++) {
if (secondArr[i][j] == " ") {
emptyIndices.push([i, j]);
}
}
}
return emptyIndices;
}
//this function returns the modified array, with empty spaces replaced with 0s
function fillWithZero(secondArr, toFill) {
var emptyIndices = findBlankSpaces(secondArr);
for (var i = 0; i < emptyIndices.length; i++) {
secondArr[emptyIndices[i][0]][emptyIndices[i][1]] = toFill[i];
}
}
//consoles
console.log(fillWithZero(secondArr, toFill));
console.log(mainArr);
//expected output in console is [[" ", 1,1,1], [" ",1,1,1], [" ",1,1,1], [" ",1,1,1]];
//actual output is [[0,1,1,1], [0,1,1,1], [0,1,1,1], [0,1,1,1]];
//I didn't modify mainArr, but only modified secondArr, why that mainArr also affected?
I didn't modify the mainArr, only created a copy by using slice()
, but why it keeps changing when its copy changes?
This question is: Any way to stop this from happening or how do I call the mainArr again without any 0s in it, I want mainArr stays unchanged. Thanks
As shown at Slice MDN, the slice method returns a shallow copy of the array that calls it. Deep copy discusses a few ways to deep copy objects in JS. A good one it mentions is
var secondArr = JSON.parse(JSON.stringify(mainArr))
This converts your array to JSON and then parses it into a new object
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