Why Math.pow(long, (1/3)) always returns 1?

Question

If problem is in power, how to write it correctly?

Answer 1

This is because 1/3 is integer division, and it evaluates to 0. You are effectively raising to the 0th power, which always yields 1. Try 1.0/3.0 instead.

Answer 2

Try Math.pow(long, 1D/3).

By default, numeric literals in Java are considered as ints. So, 1/3 is converted to 0 and not 0.33333 as should be the case. Qualifying it with 1D or 1F or 1.0 will solve the problem.