It seems that in most cases the C# compiler could call Dispose()
automatically. Like most cases of the using pattern look like:
public void SomeMethod()
{
...
using (var foo = new Foo())
{
...
}
// Foo isn't use after here (obviously).
...
}
Since foo
isn't used (that's a very simple detection) and since its not provided as argument to another method (that's a supposition that applies to many use cases and can be extended), the compiler could automatically and immediately call Dispose()
without the developper requiring to do it.
This means that in most cases the using
is pretty useless if the compiler does some smart job. IDisposable
seem low level enough to me to be taken in account by a compiler.
Now why isn't this done? Wouldn't that improve the performances (if the developpers are... dirty).
Generally, we use to call C as a middle level language. Because, the 'C' compiler combines the capabilities of an assembly language with the features of a high-level language. Therefore, it is best for writing both system software and business packages. 'C' Programs are efficient and fast.
C is a general-purpose programming language and can efficiently work on enterprise applications, games, graphics, and applications requiring calculations, etc. C language has a rich library which provides a number of built-in functions. It also offers dynamic memory allocation.
It is fast The programs that you write in C compile and execute much faster than those written in other languages. This is because it does not have garbage collection and other such additional processing overheads. Hence, the language is faster as compared to most other programming languages.
A couple of points:
Calling Dispose
does not increase performance. IDisposable
is designed for scenarios where you are using limited and/or unmanaged resources that cannot be accounted for by the runtime.
There is no clear and obvious mechanism as to how the compiler could treat IDisposable
objects in the code. What makes it a candidate for being disposed of automatically and what doesn't? If the instance is (or could) be exposed outside of the method? There's nothing to say that just because I pass an object to another function or class that I want it to be usable beyond the scope of the method
Consider, for example, a factory patter that takes a Stream
and deserializes an instance of a class.
public class Foo
{
public static Foo FromStream(System.IO.Stream stream) { ... }
}
And I call it:
Stream stream = new FileStream(path);
Foo foo = Foo.FromStream(stream);
Now, I may or may not want that Stream
to be disposed of when the method exits. If Foo
's factory reads all of the necessary data from the Stream
and no longer needs it, then I would want it to be disposed of. If the Foo
object has to hold on to the stream and use it over its lifetime, then I wouldn't want it to be disposed of.
Likewise, what about instances that are retrieved from something other than a constructor, like Control.CreateGraphics()
. These instances could exist outside of the code, so the compiler wouldn't dispose of them automatically.
Giving the user control (and providing an idiom like the using
block) makes the user's intention clear and makes it much easier to spot places where IDisposable
instances are not being properly disposed of. If the compiler were to automatically dispose of some instances, then debugging would be that much more difficult as the developer had to decipher how the automatic disposal rules applied to each and every block of code that used an IDisposable
object.
In the end, there are two reasons (by convention) for implementing IDisposable
on a type.
IDisposable
that should be disposed of when this object's lifetime is over.In the first case, all such types are supposed to implement a finalizer that calls Dispose
and releases all unmanaged resources if the developer fails to do so (this is to prevent memory and handle leaks).
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