Why is `True is False == False`, False in Python? [duplicate]

Question

Why is it that these statements work as expected when brackets are used:

>>> (True is False) == False True  >>> True is (False == False) True 

But it returns False when there are no brackets?

>>> True is False == False False 

Answer 1

Based on python documentation about operator precedence :

Note that comparisons, membership tests, and identity tests, all have the same precedence and have a left-to-right chaining feature as described in the Comparisons section.

So actually you have a chained statement like following :

>>> (True is False) and (False==False) False 

You can assume that the central object will be shared between 2 operations and other objects (False in this case).

And note that its also true for all Comparisons, including membership tests and identity tests operations which are following operands :

in, not in, is, is not, <, <=, >, >=, !=, == 

Example :

>>> 1 in [1,2] == True False