I recently wrote a computation-intensive algorithm in Java, and then translated it to C++. To my surprise the C++ executed considerably slower. I have now written a much shorter Java test program, and a corresponding C++ program - see below. My original code featured a lot of array access, as does the test code. The C++ takes 5.5 times longer to execute (see comment at end of each program).
Conclusions after 1st 21 comments below ...
Test code:
g++ -o ...
Java 5.5 times faster g++ -O3 -o ...
Java 2.9 times faster g++ -fprofile-generate -march=native -O3 -o ...
(run, then g++ -fprofile-use
etc) Java 1.07 times faster.My original project (much more complex than test code):
Software environment:
Ubuntu 16.04 (64 bit).
Netbeans 8.2 / jdk 8u121 (java code executed inside netbeans)
g++ (Ubuntu 5.4.0-6ubuntu1~16.04.4) 5.4.0 20160609
Compilation: g++ -o cpp_test cpp_test.cpp
Java code:
public class JavaTest {
public static void main(String[] args) {
final int ARRAY_LENGTH = 100;
final int FINISH_TRIGGER = 100000000;
int[] intArray = new int[ARRAY_LENGTH];
for (int i = 0; i < ARRAY_LENGTH; i++) intArray[i] = 1;
int i = 0;
boolean finished = false;
long loopCount = 0;
System.out.println("Start");
long startTime = System.nanoTime();
while (!finished) {
loopCount++;
intArray[i]++;
if (intArray[i] >= FINISH_TRIGGER) finished = true;
else if (i <(ARRAY_LENGTH - 1)) i++;
else i = 0;
}
System.out.println("Finish: " + loopCount + " loops; " +
((System.nanoTime() - startTime)/1e9) + " secs");
// 5 executions in range 5.98 - 6.17 secs (each 9999999801 loops)
}
}
C++ code:
//cpp_test.cpp:
#include <iostream>
#include <sys/time.h>
int main() {
const int ARRAY_LENGTH = 100;
const int FINISH_TRIGGER = 100000000;
int *intArray = new int[ARRAY_LENGTH];
for (int i = 0; i < ARRAY_LENGTH; i++) intArray[i] = 1;
int i = 0;
bool finished = false;
long long loopCount = 0;
std::cout << "Start\n";
timespec ts;
clock_gettime(CLOCK_REALTIME, &ts);
long long startTime = (1000000000*ts.tv_sec) + ts.tv_nsec;
while (!finished) {
loopCount++;
intArray[i]++;
if (intArray[i] >= FINISH_TRIGGER) finished = true;
else if (i < (ARRAY_LENGTH - 1)) i++;
else i = 0;
}
clock_gettime(CLOCK_REALTIME, &ts);
double elapsedTime =
((1000000000*ts.tv_sec) + ts.tv_nsec - startTime)/1e9;
std::cout << "Finish: " << loopCount << " loops; ";
std::cout << elapsedTime << " secs\n";
// 5 executions in range 33.07 - 33.45 secs (each 9999999801 loops)
}
Java is an object-oriented, high level, and interpreted language. Java uses objects, while C uses functions. Java is easier to learn and use because it's high level, while C can do more and perform faster because it's closer to machine code.
Elapsed Time. Based on these results, C is 2.34 times slower than Java and Python is 33.34 times slower than Java.
So Java code is probably easier to write but will still generally be slower than C code. However, when it comes to pure number crunching, like in my example below, there are interesting things to discover.
The only time I could get the C++ program to outperform Java was when using profiling information. This shows that there's something in the runtime information (that Java gets by default) that allows for faster execution.
There's not much going on in your program apart from a non-trivial if statement. That is, without analysing the entire program, it's hard to predict which branch is most likely. This leads me to believe that this is a branch misprediction issue. Modern CPUs do instruction pipelining which allows for higher CPU throughput. However, this requires a prediction of what the next instructions to execute are. If the guess is wrong, the instruction pipeline must be cleared out, and the correct instructions loaded in (which takes time).
At compile time, the compiler doesn't have enough information to predict which branch is most likely. CPUs do a bit of branch prediction as well, but this is generally along the lines of loops loop and ifs if (rather than else).
Java, however, has the advantage of being able to use information at runtime as well as compile time. This allows Java to identify the middle branch as the one that occurs most frequently and so have this branch predicted for the pipeline.
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