Menu
This code doesn't behave how I expect it to.
#include<iostream> using namespace std; class Class { Class() { cout<<"default constructor called"; } ~Class() { cout<<"destrutor called"; } }; int main() { Class object(); } I expected the output 'default constructor called', but I did not see anything as the output. What is the problem?
789
The reason the copy constructor is not called is because the copy constructor itself is a function with one parameter. You didn't call such function,so it didn't execute.
In C++ that statement makes a copy of the object's state. In Java it simply copies the reference. The object's state is not copied so implicitly calling the copy constructor makes no sense. And that's all there is to it really.
clone() doesn't call a constructor. You can only do this (unconditionally) if the class is final , because then you can guarantee to be returning an object of the same type as the original.
Nope. Your line Class object(); Declared a function. What you want to write is Class object;
Try it out.
You may also be interested in the most vexing parse (as others have noted). A great example is in Effective STL Item 6 on page 33. (In 12th printing, September 2009.) Specifically the example at the top of page 35 is what you did, and it explains why the parser handles it as a function declaration.
184
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
