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Why is res.send being called twice?

I'm working on creating a middleware for an express router that will execute some code for every request and response. Intercepting a request is easy and there are plenty of examples, but I have not found anything for an elegant approach to intercepting a response. After some research, the best I have come up with is to replace the send function of the response object, shown in the following snippet:

const express = require('express');
const app = express();
var router = express.Router();
var port = process.env.PORT || 3000;

router.get('/test', function(req, res) {
    res.send({
        message: "testing"
    });
});

app.use(function(req, res, next){
    console.log("INTERCEPT-REQUEST");
    const orig_send = res.send;
    res.send = function(arg) {
        console.log("INTERCEPT-RESPONSE");
        orig_send.call(res, arg);
    };
    next();
});

app.use("/api", router);
app.listen(process.env.PORT || 3000) && console.log("Running");

There's a problem with this approach: for some reason "INTERCEPT-RESPONSE" is printed in the console twice, meaning res.send is being called twice...

I can set a flag on res.locals the first time it's called to avoid processing the response twice, but I am wondering why res.send is being called twice?

like image 932
Jay Avatar asked Jan 05 '17 16:01

Jay


People also ask

Can you Res send twice?

No, you cannot call that twice for the same request. In Express, you can only use res. send() or res. json() or res.

Does Res send call res end?

res. send() is used to send the response to the client where res. end() is used to end the response you are sending.

What does Res send mean?

The res object basically refers to the response that'll be sent out as part of this API call. The res. send function sets the content type to text/Html which means that the client will now treat it as text. It then returns the response to the client.

What happens after Res send?

res. send() or res. json() should end all writing to the response stream and send the response. However, you absolutely can call next() if you want to do further processing after the response is sent, just make sure you don't write to the response stream after you call res.


1 Answers

Better example

Try this code to see what are the arguments passed to res.send:

const express = require('express');
const app = express();
var router = express.Router();
var port = process.env.PORT || 3000;

router.get('/test', function(req, res) {
    console.log('ACTUAL RESPONSE');
    res.send({
        message: "testing"
    });
});

app.use(function(req, res, next){
    console.log("INTERCEPT-REQUEST");
    const orig_send = res.send;
    res.send = function(arg) {
        console.log("INTERCEPT-RESPONSE", JSON.stringify(arguments));
        orig_send.call(res, arg);
    };
    next();
});

app.use("/api", router);
app.listen(process.env.PORT || 3000, function () {
    console.log("Running");
});

(I also changed the printing of "Running" to print it when the server is actually listening - your code && was printed before the server was listening - but that's not that important here).

Now after running:

curl http://localhost:3000/api/test

the output on the server console is:

Running
INTERCEPT-REQUEST
ACTUAL RESPONSE
INTERCEPT-RESPONSE {"0":{"message":"testing"}}
INTERCEPT-RESPONSE {"0":"{\"message\":\"testing\"}"}

What happens

As you can see your handler is actually called once by your code, with an object as the first (and only) argument. But then it is called once again with an object serialized to JSON. This is how res.send internally works - see below for details. Since you put your intercepting function on the actual response object then I guess it is calling itself with JSON argument and it doesn't even know that it calls your function in the meantime.

How to avoid it

Try it with the object serialized to JSON by yourself:

const express = require('express');
const app = express();
var router = express.Router();
var port = process.env.PORT || 3000;

router.get('/test', function(req, res) {
    console.log('ACTUAL RESPONSE');
    res.send(JSON.stringify({
        message: "testing"
    }));
});

app.use(function(req, res, next){
    console.log("INTERCEPT-REQUEST");
    const orig_send = res.send;
    res.send = function(arg) {
        console.log("INTERCEPT-RESPONSE", JSON.stringify(arguments));
        orig_send.call(res, arg);
    };
    next();
});

app.use("/api", router);
app.listen(process.env.PORT || 3000, function () {
    console.log("Running");
});

Now it prints:

Running
INTERCEPT-REQUEST
ACTUAL RESPONSE
INTERCEPT-RESPONSE {"0":"{\"message\":\"testing\"}"}

Calling the res.send only once.

Explanation

Now, this is the code that handles object arguments to res.json:

  if (chunk === null) {
    chunk = '';
  } else if (Buffer.isBuffer(chunk)) {
    if (!this.get('Content-Type')) {
      this.type('bin');
    }
  } else {
    return this.json(chunk);
  }

See: https://github.com/expressjs/express/blob/master/lib/response.js#L144-L154

You get the else branch and it calls this.json() (which is res.json() really) with your argument.

But guess what - res.json() calls res.send() in this line:

return this.send(body);

See: https://github.com/expressjs/express/blob/master/lib/response.js#L250

Which calls your intercepting function (for the second time) before running the real res.send().

So, mystery solved. :)

like image 151
rsp Avatar answered Nov 08 '22 11:11

rsp