Why is my for loop not taking 9 inputs?

Question

My code only takes 5 values as input.? What am i doing wrong?

#include<stdio.h>
#include<stdlib.h>
int main()
{
    char arr[3][3];
    int i,j,n;
    for(i=0;i<3;i++)
    {
        for(j=0;j<3;j++)
        {
            scanf("%c",&arr[i][j]);
        }
    }
    return 0;
}

How should i correct it?

Answer 1

Change

scanf("%c",&arr[i][j]);

to

scanf(" %c",&arr[i][j]);.

Notice the space given before specifier to consume \n left in stdin buffer when you pressed enter.

Each \n is working as input taking your space from input space.