Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Why is my file not being loaded?

I am simply trying to upload a file and nothing is working.

 <!DOCTYPE html>
 <html><body>

            <form id="exp" enctype = "multipart/form-data" action="../cgi-bin/uploadPic.php">
                <input type="file" id="profilePic2" name="newPic"></input> <br /><br /><br />
                <input type="submit" value="Upload Pic" style="color:black;"></input>
            </form>
  </body></html>

My php file is being executed. Please mind the sloppy code, I am trying to debug via echo.

 <html>
 <body>
 <?php

$loadFile = true; // error code
$allowedExts = array("jpg","jpeg","gif","png");
$extension = end(explode(".", $_FILES["newPic"]["name"]));

$file = $_FILES["newPic"];
$picIncluded = false;

if((    ($_FILES["newPic"]["type"] == "image/gif")
||  ($_FILES["newPic"]["type"] == "image/jpeg")
||  ($_FILES["newPic"]["type"] == "image/png")
||  ($_FILES["newPic"]["type"] == "image/pjpeg"))
&&  ($_FILES["newPic"]["size"] < 5000000)
&&  in_array($extension, $allowedExts)){
    if($_FILES["newPic"]["error"] > 0){
        echo "pnl"; // error code returned to client
    }
    else if(file_exists("../profile-pics/" . $file["name"])){
        echo "pld"; // picture loaded duplicate
    } else {
        $picIncluded = true;
        echo "finally";
        if(move_uploaded_file($file["name"]["tmp_name"],"./" . $file["name"])){
            echo "Success again!";
        }
        $path = "../profile-pics/" . $file["name"];
    }
}
if(is_uploaded_file($_FILES["newPic"]["name"]["tmp_name"])){
    echo "Good news!";
}

 ?>

 </body>
 </html>

Anyway, the function move_uploaded_file() is returning false since it can't find the temp file. is_uploaded_file() is also return false. My extensions and everything is correct but still to no avail, there is no file being uploaded. How can I debug this?

like image 274
Dr.Knowitall Avatar asked Mar 13 '13 04:03

Dr.Knowitall


Video Answer


1 Answers

change this

if(move_uploaded_file($file["name"]["tmp_name"],"./" . $file["name"])){

to

if(move_uploaded_file($file["tmp_name"],"./" . $file["name"])){

because you have assigned

$file = $_FILES["newPic"];
like image 127
Yogesh Suthar Avatar answered Oct 04 '22 09:10

Yogesh Suthar