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Why is instanceof operator allowed on an unbounded wild card type but not on other parameterized types in Java?

Tags:

java

generics

I think due to type erasure , using instanceof and class literals are not allowed for parameterized generic types except unbounded wild card types . Why did the Java language designers allowed this exception ? There isn't any role of type erasure for unbounded wild card types ?

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Geek Avatar asked Feb 19 '13 13:02

Geek


1 Answers

The point is that an object knows its concrete class - but not the generic type arguments for that. So if we construct an ArrayList<Integer>, that knows at execution time that it's an ArrayList of some kind - but it doesn't know about the Integer part.

The "ArrayList of some kind" part is precisely what ArrayList<?> means, which is why:

if (foo instanceof ArrayList<?>)

is valid. It's just equivalent to using the raw type:

if (foo instanceof ArrayList)
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Jon Skeet Avatar answered Oct 06 '22 00:10

Jon Skeet