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Why does the following compile in GCC 4.8 (g++)? Isn't it completely ill-formed?
void test(int x)
{
return test(3);
}
int main() {}
test, which does not existtest
Both should be fundamentally impossible — not just UB, as far as I can recall — with a void return type.
The only warning I get is about x being unused, not even anything about a non-standard implicit return type being added.
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Return from void functions in C++ The void functions are called void because they do not return anything. “A void function cannot return anything” this statement is not always true. From a void function, we cannot return any values, but we can return something other than values. Some of them are like below.
Void functions, also called nonvalue-returning functions, are used just like value-returning functions except void return types do not return a value when the function is executed. The void function accomplishes its task and then returns control to the caller. The void function call is a stand-alone statement.
Void functions are created and used just like value-returning functions except they do not return a value after the function executes. In lieu of a data type, void functions use the keyword "void." A void function performs a task, and then control returns back to the caller--but, it does not return a value.
type function-name (formal parameter type list); A void function with value parameters are declared by enclosing the list of types for the parameter list in the parentheses. To activate a void function with value parameters, we specify the name of the function and provide the actual arguments enclosed in parentheses.
That's allowed by the standard (§6.6.3/3)
A return statement with an expression of type void can be used only in functions with a return type of cv void; the expression is evaluated just before the function returns to its caller.
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