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Why is fseeko() faster with giant files than small ones?

I'm getting some strange performance results here and I'm hoping someone on stackoverflow.com can shed some light on this!

My goal was a program that I could use to test whether large seek's were more expensive than small seek's...

First, I created two files by dd'ing /dev/zero to seperate files... One is 1 mb, the other is 9.8gb... Then I wrote this code:

#define _LARGE_FILE_API
#define _FILE_OFFSET_BITS 64

#include <stdio.h>
#include <stdlib.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <unistd.h>

int main( int argc, char* argv[] )
{
  struct stat64 fileInfo;
  stat64( argv[1], &fileInfo );

  FILE* inFile = fopen( argv[1], "r" );

  for( int i = 0; i < 1000000; i++ )
    {
      double seekFrac = ((double)(random() % 100)) / ((double)100);

      unsigned long long seekOffset = (unsigned long long)(seekFrac * fileInfo.st_size);

      fseeko( inFile, seekOffset, SEEK_SET );
    }

    fclose( inFile );
}

Basically, this code does one million random seeks across the whole range of the file. When I run this under time, I get results like this for smallfile:

[developer@stinger ~]# time ./seeker ./smallfile

real    0m1.863s
user    0m0.504s
sys  0m1.358s

When I run it against the 9.8 gig file, I get results like this:

[developer@stinger ~]# time ./seeker ./bigfile

real    0m0.670s
user    0m0.337s
sys  0m0.333s

I ran against each file a couple dozen times and the results are consistent. Seeking in the large file is more than twice as fast as seeking in the small file. Why?

like image 667
dicroce Avatar asked Dec 08 '22 02:12

dicroce


1 Answers

You're not measuring disk performance, you're measuring how long it takes for fseek to set a pointer and return.

I recommend you do a file read from the location you're seeking to, if you want to test real IO.

like image 86
Carl Smotricz Avatar answered Dec 09 '22 14:12

Carl Smotricz