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Why is ES6 "yield" a reserved word when called in this context?

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I am using node 4.1.1. When I run this code

"use strict";  function *generator() {   let numbers = [1,2,3,4,5];   numbers.map(n => yield (n + 1)); }  for (var n of generator()) {   console.log(n); } 

I get this error

  numbers.map(n => yield (n + 1));                    ^^^^^  SyntaxError: Unexpected strict mode reserved word 

If I rearrange the code to be this

"use strict";  function *generator() {   let numbers = [1,2,3,4,5];   let higherNumbers = numbers.map(n => n + 1);   for(let i=0;i<higherNumbers.length;i++) {     yield higherNumbers[i];   } }  for (var n of generator()) {   console.log(n); } 

I get the expected result.

Why does the second one work, and the first fail? And surely if a keyword is reserved, it's reserved in all contexts, not just when it's used in a arrow function?

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Mike Hogan Avatar asked Oct 24 '15 09:10

Mike Hogan


1 Answers

It is because arrow functions are not generator functions. For example,

function temp() {   yield 1; } 

Can we expect this to work? No. Because temp is not a generator function. The same is applicable to arrow functions as well.


FWIW, the usage of yield in an Arrow function is an early error as per the ECMAScript 2015 specification, as per this section,

ArrowFunction : ArrowParameters => ConciseBody

  • It is a Syntax Error if ArrowParameters Contains YieldExpression is true.

  • It is a Syntax Error if ConciseBody Contains YieldExpression is true.

like image 193
thefourtheye Avatar answered Sep 23 '22 04:09

thefourtheye