Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Why is "error: invalid application of 'sizeof' to an incomplete type using unique_ptr" fixed by adding an empty destructor? [duplicate]

Tags:

I am Pimpling off the class STFT. Compiles just fine with this in the header:

class STFT; // pimpl off to prevent point name clash

class Whatever
{
private:
    STFT* stft;

and this in the implementation:

#include "STFT.h"
Whatever::Whatever() : stft(new STFT()) {
// blah blah
}

Whatever::~Whatever() {
    delete stft; // pure evil
}

However, switching to std::unique_ptr<STFT> stft; over the raw pointer in the header, and removing the destructor, I get

error: invalid application of 'sizeof' to an incomplete type 'STFT' static_assert(sizeof(_Tp) > 0, "default_delete can not delete incomplete type");

But if I simply supply an empty destructor Whatever::~Whatever(){}, then it compiles fine. This has me completely stumped. Please fill me in on what this meaningless destructor is doing for me.

like image 746
learnvst Avatar asked Dec 03 '15 17:12

learnvst


2 Answers

My usual idiom for providing such destructors is (in the implementation file):

#include "STFT.h"

Whatever::~Whatever() = default;

The important thing is that it needs to be somewhere where the pointed-to type(s) are complete.

like image 42
Toby Speight Avatar answered Sep 18 '22 20:09

Toby Speight


If we go to the cppreference document for std::unique_ptr:

std::unique_ptr may be constructed for an incomplete type T, such as to facilitate the use as a handle in the Pimpl idiom. If the default deleter is used, T must be complete at the point in code where the deleter is invoked, which happens in the destructor, move assignment operator, and reset member function of std::unique_ptr. (Conversely, std::shared_ptr can't be constructed from a raw pointer to incomplete type, but can be destroyed where T is incomplete).

We can see in the below code:

#include <memory>

class STFT; // pimpl off to prevent point name clash

class Whatever
{
    public:
     ~Whatever() ;
    private:
      std::unique_ptr<STFT> stft;
} ;

//class STFT{};

Whatever::~Whatever() {}

int main(){}

The requirements are not fulfilled when the defintion of STFT is commented before the destructor of Whatever is defined since this requires the destructor for stft which in turn requires STFT to be complete.

So it seems likely that in your implementation file STFT is complete when Whatever::~Whatever() is defined but otherwise the defaulted one is created without the STFT being complete.

like image 182
Shafik Yaghmour Avatar answered Sep 20 '22 20:09

Shafik Yaghmour