In a php file i have used include
to include the following js.php file and prior to that i have included the jquery file.
<script type="text/javascript"> $(document).ready(function(){ alert("hello"); }); </script>
But it doesn't work. Why? when I skip the $(document).ready function it works.
But i need jquery code inside. what is wrong?
$( document ). ready()A page can't be manipulated safely until the document is "ready." jQuery detects this state of readiness for you. Code included inside $( document ). ready() will only run once the page Document Object Model (DOM) is ready for JavaScript code to execute.
ready() and $(window). load() event is that the code included inside onload function will run once the entire page(images, iframes, stylesheets,etc) are loaded whereas the $(document). ready() event fires before all images,iframes etc. are loaded, but after the whole DOM itself is ready.
So technically they are both the same. Not major difference between these two declaration. They used based on weather you use JavaScript then you should use $(document). ready declaration in other case you use jQuery library which is a part of JavaScript then you should use $(function) declaration.
ready' function in a page? Can we add more than one 'document. ready' function in a page? Yes we can do it as like I did in below example both the $(document).
The most likely answer, based on what you have said, is that the core jQuery file is not actually included correctly in the page. You need something like:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
Chances are, this is missing or typed incorrectly.
Another cause that will silently fail, and all remaining callbacks never called:
$(document).ready(null);
So check if you have variables or syntax errors that return null. Like this one:
$(document).ready(function($){}(jQuery));
Notice that the function above is called instantly and undefined is returned.
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