I have a CustomObject object which overrides GetHashCode(). I have a HashSet, and I am able to call add with two distinct object having the same hash code. Both get added and later on I end up with some database insertion troubles (primary key duplicates)... The purpose of using a hashSet was connected to these database insertions (avoiding key collisions).
Am I possibly missing out on some properties of HashSet ? Even when I try checking (.Contains) before adding (.Add), I end up adding hashCode duplicates...
Because a and b and c , so it's name is C. C came out of Ken Thompson's Unix project at AT&T. He originally wrote Unix in assembly language. He wrote a language in assembly called B that ran on Unix, and was a subset of an existing language called BCPL.
Because C comes after B The reason why the language was named “C” by its creator was that it came after B language. Back then, Bell Labs already had a programming language called “B” at their disposal.
Being a middle-level language, C reduces the gap between the low-level and high-level languages. It can be used for writing operating systems as well as doing application level programming. Helps to understand the fundamentals of Computer Theories.
Because HashSet<T>
membership is based on object equality, not hash code equality. It's perfectly legal for every member of a HashSet<T>
to have the same hash code as long as the members are different according to Equals
. The role that hash codes play in HashSet<T>
is for rapid testing of membership. If you have an object and its hash code is not in the HashSet<T>
, then you know that the object is not in the HashSet<T>
. If you have an object and its hash code is in the HashSet<T>
, then you have to walk the chain of objects with that same hash code testing for equality using Equals
to see if the object is actually in the HashSet<T>
or not. That's why a balanced hash code distribution is important. But it is not the case that unique hash codes are necessary.
Overriding GetHashCode is not enough. You need to override Equals function as well.
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