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Why this [.]+ Java regular expression doesn't match my "foo" text, while .+ matches perfectly (tested here)?
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If you want to remove the [ or the ] , use the expression: "\\[|\\]" . The two backslashes escape the square bracket and the pipe is an "or".
Just make sure ] is the first character (or in this case, first after the ^ . result2 = Regex. Replace(result2, "[^][A-Za-z0-9/.,>#:\s]", "");
Although dot ( . ) has special meaning in regex, in a character class (square brackets) any characters except ^ , - , ] or \ is a literal, and do not require escape sequence.
Use square brackets as escape characters for the percent sign, the underscore, and the left bracket. The right bracket does not need an escape character; use it by itself. If you use the hyphen as a literal character, it must be the first character inside a set of square brackets.
[.] is equivalent to escaping the . (dot) character, i.e. \\..
Once the character appears in a character class, it loses its status as a special character.
As foo doesn't contain any dots, nothing is matched. .+, on the other hand, is a wildcard greedy expression that matches everything.
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